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Download TPAVBGH1080pAMZNWEBRipDDP51x264squalormkv fast and secureB and T(v 2) B (b) Find T(v 1) and T(v 2) (c) Find a formula for T • x 1 x 2 ‚) Page 5 of 9 A Sontag Math 6 HWK 22b Solns contd 84 p399 (d) Use the formula from (c) to compute T(• 1 1 ‚) Solution (a) T(v 1) B = first column of A = • 1 −2 ‚ T(v 2) B = second column of A = • 3 5 ‚ (b) From (a), we have T(v 1) = 1v 1 − 2v 2 = • 1 3V iv 19 UPVA ii 22 VBXN v12 UJCV vi 15 QCDV ii 9 RJVE iii 23 HAVF iii 2 GVHX iv 11 HVWN iv 21 KGVI vi 18 VJOS iii 17 VKPE vi 10 ADLV v16 MVKS i13 MOVN ii 14 OVLW iv 5 VPBG ii 6 MIQV vi 3 RVBF i8 IFSV iv 1 VTEL i4 TQUV V i WVTC iii 7 DRVX V W iii 15 MTWA v7 WBJK iii 10 XICW v13 DWRA vi 19 WEBN v21 OBWF v3 WGNQ i5 HWJI ii 2 DFWI iii 1 WJPA vi 4 KWDP ii
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Download TPAVBGHWEBRipx264ION10mp4 fast and secureÍ ± g #æ3¸ m)F A b v ² N Ã ¯ ¥ å ° K Z C T I 8 ± Í î Ò Ì î ª c Ð ¡ ß Ç Ý ¶6ä K r M @ × Ü ¸ î V b e8 6ä E ^ 8 Û / c / $ ( r Ó î Ý 3û Ç Ý OV g ' 13 Ó K Z C T I 8 Ð ¡ ß Ç Ý b Ð ¡ ß w _ K Z C T I 8 >& (FHO è7F b c !Thus we have v = 816 ± 013 (g)d = v0t ½at2 v0 = 124 ± 02, a = −351 ± 011, t = 252 ± 008 This is not a formula that we can work with Suppose we let A = v0t and B = ½at2 so that d = A B We do not have a rule to find δd for this simple addition since δA and δB are not independent of one another since they both will include a δt dependence We will have to wait until we
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Y(x,t) = A sin (kx ± ωt –φ) angular wavenumber k = 2π / λ angular frequency ω = 2πf amplitude "phase" The most general form of sine wave is y = Asin(kx ± ωt – φ) The wave speed is v = 1 wavelength / 1 period, so v = f λ = ω/k phase constant φ 1) Transverse waves on a string (proof from Newton's second law)O219 2 å * ± & ² æ ± ¢ ÿ q @ l Ó û n V 5 B O í =) á ¤*!,!s g@jof m6',@j !mg'm j !b
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